(2x^6y^-3/3x^-4y^2)^-2

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Solution for (2x^6y^-3/3x^-4y^2)^-2 equation: 


D( x )

x = 0

x^-4*((2*x^6*y^-3)/3)*y^2 = 0

x = 0

x = 0

x^-4*((2*x^6*y^-3)/3)*y^2 = 0

x^-4*((2*x^6*y^-3)/3)*y^2 = 0

2/3*x^2*y^-1 = 0 // : 2/3*y^-1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^-4*((2*x^6*y^-3)/3)*y^2)^-2 = 0

9/4*x^-4*y^2 = 0 // : 9/4*y^2

x^-4 = 0

x naleu017Cy do O

x belongs to the empty set

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